Assuming that (scan) is a properly initialized scanner variable, which of the following correctly inputs a double?

Homework Help: Questions and Answers: Assuming that (scan) is a properly initialized scanner variable, which of the following correctly inputs a double?

Assuming that (scan) is a properly initialized scanner variable, which of the following correctly inputs a double?
A. double val = scan.nextLine();
B. double val = scan.nextDouble();
C. double val = nextDouble();
D. double val = scan.nextValue();
E. double val = scan.nextpouble;

A. double val = scan.nextLine();
B. double val = scan.nextDouble();
C. double val = nextDouble();
D. double val = scan.nextValue();
E. double val = scan.nextpouble;

Answer:

First, let’s understand the questions: It’s about to determine the correct way to input a double value using a Scanner object.

Given Options: Step by Step Answering

a) double val = scan.nextLine();

  • nextLine() reads an entire line of input as a String, not as a double.
  • This is incorrect because it will not convert the input to a double.

b) double val = scan.nextDouble();

  • nextDouble() is the correct method in the Scanner class to read the next input as a double directly.
  • This is correct because this method reads and converts the input into a double.

c) double val = nextDouble();

  • This calls nextDouble() without specifying the scan object (which is the Scanner instance).
  • This is incorrect because it doesn’t reference the scanner object.

d) double val = scan.nextValue();

  • There is no method called nextValue() in the Scanner class.
  • This is incorrect because this method doesn’t exist.

e) double val = scan.nextpouble;

  • This has a typo. There is no method nextpouble().
  • This is incorrect due to the syntax error.

Final Answer

Based on the above analysis, the correct answer is:

b) double val = scan.nextDouble();

This method call will read the next token from the input as a double value.

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